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1.4r^2=42
We move all terms to the left:
1.4r^2-(42)=0
a = 1.4; b = 0; c = -42;
Δ = b2-4ac
Δ = 02-4·1.4·(-42)
Δ = 235.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{235.2}}{2*1.4}=\frac{0-\sqrt{235.2}}{2.8} =-\frac{\sqrt{}}{2.8} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{235.2}}{2*1.4}=\frac{0+\sqrt{235.2}}{2.8} =\frac{\sqrt{}}{2.8} $
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